2.5x^2+25-300=0

Solution for 2.5x^2+25-300=0 equation:

2.5x^2+25-300=0

We add all the numbers together, and all the variables

2.5x^2-275=0

a = 2.5; b = 0; c = -275;
Δ = b2-4ac
Δ = 02-4·2.5·(-275)
Δ = 2750
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2750}=\sqrt{25*110}=\sqrt{25}*\sqrt{110}=5\sqrt{110}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-5\sqrt{110}}{2*2.5}=\frac{0-5\sqrt{110}}{5}
=-\frac{5\sqrt{110}}{5}
=-\sqrt{110}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+5\sqrt{110}}{2*2.5}=\frac{0+5\sqrt{110}}{5}
=\frac{5\sqrt{110}}{5}
=\sqrt{110}
$